Graph the line using a point and a slope. write the equation of each line. f a line that passes through the point (–1, –4) and whose slope is –2.

Dos rectas cuyas pendientes son m1 y m2, son perpendiculares si y sólo si m1m2 =-1

with a point and the slope you can find the equation

y-y1=m(x-x1)

as the point is given (-1,-4) then substitute it in the equation

y-(-4)= -2[(x-(-1)]⇒y+4= -2x-2⇒y=-2x-2-4⇒y=-2x-6 and this is the equation of the line that must be graphed

second step)

graph the equation y =- 2x-6, with the points of intersection are for  x = 0, y = -2(0)-6= -6 , the point is ( 0,-6) and the other point is for y = 0  

0= -2x-6,  2x= -6, x = -6/ 2 = -3, the other point is (-3,0) then the graph is the following,   you can see in it the points of intersection

answer: bearing in mind that a rectangle has a perimeter of length + length + width + width.

step-by-step explanation:

p = perimeter

l = length

x=width

p = 2l + 2x

p = 2(l+x)     < ==== perimeter of the base of the box.

step-by-step explanation: it is d