The given line passes through the points (0, −3) and (2, 3). what is the equation, in point-slope form, of the line that is parallel to the given line and passes through the point (−1, −1)? y + 1 =(blank) (x + 1)

The equation would be y + 1 = 3(x + 1)

Step-by-step explanation:

In order to find the equation of this line, we have to use the slope formula to find the slope.

m (slope) = (y2 - y1)/(x2 - x1)

m = (3 - -3)/(2 - 0)

m = (3 + 3)/(2 - 0)

m = 6/2

m = 3

Now that we have that, we can use it along with the second point to put into the point-slope equation.

y - y1 = m(x - x1)

y - -1= 3(x - -1)

y + 1 = 3(x + 1)

positive

step-by-step explanation:

the quadrant is facing upwards

y = 3x+4

step-by-step explanation:

to find the slope

slope = (y2-y1)/ (x2-x1)

    = (-8-4)/ (-4-0)

    = -12/-4

  = 3

using the slope intercept form of a line

y= mx+b

we know the slope is 3

we know the y intercept is 4 ( the point where it crosses the y axis or x=0)

y = 3x+4