What is the equation of a line thatvis parallel to -x+3y=6 and passes through the point (3, 5)

First off: we need to find the slope. You can do that by taking a x over a negative y. In this case, that will be 1/3

Next: you put what you know into the appropriate form. As you have a point and a slope, you'll need the point-slope intercept form. This is: y-y1=m(x-x1). Everything plugged in looks like: y-5=1/3(x-3)

Finally: you solve. You first take 1/3 and distribute it across the parenthesis. That gives you y-5=1/3x-1. Then, you get y by itself.

Your answer is: y=1/3x+4

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