The solution to the system of equations 6x-3y=3 and -2x+6y=14

6x - 3y = 3 = -2x+6y = 14
+2x. +2x
8x - 3y = 3 = 6y = 14
+3y. +3y
8x = 3 = 9y = 14

6x-3y=3
-2x+6y=14
Elimination:
cancel out one of the variable to =0
(6x-3y=3)2
+
-2x+6y=14


12x-6y=6
+
-2x+6y=14

10x+0y=20

2. get X by itself

10x÷10= 1x. and 20÷10=2 so x=2

3. Now plug x=2 back into the second equation to find Y

-2(2)+6y=14
-4+6y=14

4. Get Y by itself

-4+6y=14
+4. -4
6y=10
÷6. ÷6
y=10/6 (simplify the fraction to: 5/2)

Your answers should be Y=5/3 and X=2

Just plug both of these numbers into each equation for the variable other represents to check your work.