What is the equation of the line, in slope-intercept form, that passes through the point (0,7) and is perpendicular to the line y=3x−5?

Step-by-step explanation:

The slope-intercept form is: ; where m is the slope, and b is the y-axis interception.

So, the problem is asking for a line that it's perpendicular to . This perpendicular relation means that the line we have to find have an inverse and opposite slope than the given line, that's expressed like this:

That expression is the condition to have perpendicular lines. So, the given line has a slope of 3, now we can find the slope of the new line:

Now we have the slope of the new perpendicular line, we use the point-slope formula to find its equation:

Therefore, the slope-intercept form of the new perpendicular line is:

step-by-step explanation: step 3 should really go to step seven, but anyway never mind.

1 ∠oln ≅ ∠lno

a4 - 3a2 - 1

step-by-step explanation:

step   1   :

equation at the end of step   1   :

  ((a4) -   3a2) -   1

step   2   :

trying to factor by splitting the middle term

2.1     factoring   a4-3a2-1  

the first term is,   a4   its coefficient is   1 .

the middle term is,   -3a2   its coefficient is   -3 .

the last term, "the constant", is   -1