What are the actual dimensions of a television that has a 15: 9 aspect ratio and a screen that is 42 inches?

Let x be the number.

It is given that a 15 : 9 aspect ratio and a screen that is 42 inches.

Aspect ratio states that  the ratio of the display image’s width to its height.

Then;

Width of the television of(w) = 15x

and height of the television(h) = 9x.

Since, television is in the form of Rectangle.

And it is also, given that the screen is 42 inches .

⇒Diagonal of the television(D) = 42 inches

Using formula of diagonal of the rectangle :

Substitute the given values to solve for x;

or

Then:

width of the television (15x) = 15(2.4) = 36 inches and

Height of the television (9x) = 9(2.4) = 21.6 inches.

Therefore, the actual dimensions of the television are;

width = 36 inches and height = 21.6 inches.

a² + b²= c²

24² + 7² = c²

c= 25

x=half

step-by-step explanation: