Solve a right triangles with an acute angle of 14° and hypotenuse length of 100m. express the angle to the nearest degree and the lengths to the nearest tenth of a metre.

90 0 + 140 = 1040 100m 760 180-1040 : 76 100 sm (140) Use law of sines : 100 , 1-Sinz (149) 100 22 sin (909) sm(149) cross multiply 1 sm(90 0) = 100 sin ( 140 ) X = 100 Sch (14') Sm( 90) 1 : 100 sm (149) Now , use the pythagorean theorem to solve for the other side. ZOO1 : (Cohi)us ool ) (Cohi)WS 001 ) + 20 a2 + 100 00 sm? (140) = 100 00 Q2 = 10000 - 100 00 sm ( 140 ) a : 10ON 1-sm2 (149 )

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