Use the table to determine the appropriate model of the function, x       0             1             2             3             4       f(x)       3             7             29             87             199       linear quadratic cubic exponential

Points Lying on the undefined curve are

x :   0     1      2     3      4

f(x): 3    7     29    87    199

Plotting the points on the coordinate plane

As you will see, the value of x increases , value of y increases .

It is not linear, because slope between two points is not same.

Neither quadratic nor cubic  , it is not cutting x axis .

So, As value of x increases, value of y does not increases by a fixed quantity, but it increases.

So, option (D) Exponential ,Function word is the right word Describing these points.  

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !