Question 3 options:
triangle abc has the following coordinates:

a (-2, 3)

b (4, -3)

c (-2, -3)

what are the coordinates points for triangle a'b'c' if the scale factor is −34.

a'

b'

c'

Hence, the coordinates of A',B' and C' are:

A' (68,-102)

B' (-136,102)

C' (68,102)

Step-by-step explanation:

We are given a Triangle ABC such that:

The vertex of the triangle are given as:

A (-2, 3)

B (4, -3)

C (-2, -3)

Now it is given that:

The triangle ABC has been dilated to form triangle A'B'C'  with a scale factor of -34.

This means that:

A → A'

B → B'

and C → C'

We are asked to find the coordinates points for triangle A'B'C'.

We know that if there is a dilation with some scale factor 'k' then the coordinates of the transformed image get multiplied by the same scale factor.

i.e. coordinates of A'=(-34×(-2),(-34)×3)=(68,-102)

coordinates of B'=(-34×4,(-34)×(-3))=(-136,102)

and coordinates of C'=(-34×(-2),-34×(-3))=(68,102)

Hence, A (-2,3) → A' (68,-102)

B (4,-3) → B' (-136,102)

C (-2,-3) → C' (68,102)

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)

the answer would be 44.79

plz mark brainliest

step-by-step explanation: