∠bec is formed inside a circle by two intersecting chords. if minor arc bd = 94 and minor arc ac = 166, what is the measure of ∠ bec? a) 44° b) 47° c) 50° d) 53°

∠BEC = 50°

Step-by-step explanation:

For better understanding of the solution, see the attached figure of the problem :

Minor arc BD = 94

Minor arc AC = 166

Now, the angle formed by the intersection of the two chords is ∠BED

And, the angle formed by the intersection of two chords is half the sum of angle measures of the corresponding chords.

Now, ∠BED + ∠BEC = 180 ( Adjacent angles )

⇒ ∠BEC = 180 - 130

⇒ ∠BEC = 50°

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!

10 you would take 50/ .2

step-by-step explanation: