Let u=ln x and v= ln y. write y^3x^5 in terms of u and v

3v + 5u

Step-by-step explanation:

Write z = y^3 x^5 in terms of u and v.

Take the natural log (ln) of both sides.  Then:

ln z = 3 ln y + 5 ln x

Substituting u for ln x and v for ln y, we get:

ln z = 3v + 5u (answer)

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

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