How to slove this
i need surface and radius

e) Area of shaded part = a^2(1 - 0.25 π). Radius of the arc = 0.5a.

f) Area of shaded part =   0.5a^2( π - 2). Radius of the arcs = a.

Step-by-step explanation:

e) Area of shaded part = area of the square - area of the 2 semicircles

= a^2 - 2 * 0.5 π r^2

= a^2 -  π (0.5a)^2

= a^2 - 0.25 a^2 π

= a^2(1 - 0.25π )

The radius of the semicircle is 0.5a.

f)  Split the shaded area into 2 parts by drawing the diagonal of the square through the shaded area.

The area of one half = the area of the quarter circle  - area of the triangle formed by the  diagonal

= 0.25  π a^2 - 0.5a^2

=  0.25 a^2 π - 0.5a^2

= 0.25a^2( π  - 2)

So the total area of the shaded area

= 2 * 0.25a^2( π  - 2)

= 0.5a^2( π - 2).

80 the answer is 80

step-by-step explanation:

the rocket cannot penetrate the ground, in a contextual sense, therefore the roots of this equation should be the domain of this function. i'll let you find the roots of this quadratic equation (hint: use the quadratic formula:  

1- c

2-a

step-by-step explanation:

mark brainliest!