Subtract 14w+4 from 12w+3 .
a,14w−1

b.−14w+1

c.14w+7

d.−14w+7

c.1/4w+7

Step-by-step explanation:

1/2w+3 - (1/4w-4)

Distribute the minus sign

1/2w+3 - 1/4w +4

Get a common denominator for the fractions

2/4w - 1/4 w +3 +4

Combine like terms

1/4w +7

for this case we have by definition, if two lines are perpendicular, then the product of their slopes is -1.

then, given the following line:

so,

we are looking for m_ {2}:

then, the line is given by:

we find "b" replacing the given point:

finally, the equation is:

option c

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation: