Arectangular ponds refectuons in a part is 16 feet long. the maintenance crew placed a string of flags 20 feet long across the pond diagonally as shown below. what is the width of the pond

width = 12 ft

Step-by-step explanation:

Given the figure of the pond and the fact that the corners form a right triangle that is across from the string of flags, you can use the Pythagorean Theorem to solve for the width of the triangle that is formed by the flags:

a² + b² = c², where 'a' and 'b' represent the legs of the triangle and 'c' represents the diagonal or hypotenuse.  Using 16 for 'a' and 20 for 'c':

16² + b² = 20²

256 + b² = 400

Subtract 256 from both sides: 256 - 256 + b² = 400 - 256 or b² = 144

Take the square root of both sides:  √b² = √144  or b = 12 ft

75%

step-by-step explanation:

"image"

step-by-step explanation:

in most of these problems, the notation is that the point with a "prime" is the image of the point without. that is, b' is the image of b.

here, there is no dilation or reflection. there is simply translation (with no direction shown). which figure you call the "preimage" and which one you call the "image" is up to you. as a matter of convention, the naming is as described above.