What is the vertex of the graph of y=3(x-1)2+2
a) (1,-2)
b) (1,2)
c) (-1,2)
d) (3,2)

  B)  (1,2)

Step-by-step explanation:

In the vertex form ...

  y = a(x-h)^2 +k

the vertex is (h, k).

Matching the form to the given equation, we see h=1, k=2. So, the vertex is ...

  (1, 2) . . . . matches choice B

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation:

i dont know men

step-by-step explanation: