Aspinner has 6 equal sectors labeled a, b, c, d, e and f on it. the spinner is spun twice.

what is the probability of spinning b and then e, given that the spinner shows b on the first spin?

a. 1/2

b. 1/3

c. 1/6

d. 1/36

C.  

Step-by-step explanation:

Given: A spinner has 6 equal sectors labeled A, B, C, D, E and F on it. The spinner is spun twice.

If it is given that the  spinner shows B on the first spin, then the total outcomes will be{ (B,A), (B,B), (B,C), (B,D), (B,E), (B,F)}=6

The number of favorable outcome = 1

Now, the probability of spinning B and then E, given that the spinner shows B on the first spin=

answer is 67%

step-by-step explanation:

34

step-by-step explanation: