Consider the equation below. f(x) = 4x3 + 15x2 − 150x + 9 (a) find the intervals on which f is increasing. (enter your answer using interval notation.)

Increasing on (-∞, -5) and (2.5, ∞)

Step-by-step explanation:

ƒ(x) = 4x³ + 15x² - 150x + 9

Step 1.Find the zeros of the first derivative of the function

ƒ'(x) = 12x² + 30x -150 = 0

             2x² + 5x - 25 = 0

             (x + 5)(2x - 5) = 0

               x = -5 or x = 2.5

These are your critical points.

Step 2. Apply the first derivative test.

Test all intervals to the left and to the right of these values to determine if the derivative is positive or negative.

(a) x = -10

ƒ'(-10) = 12(-10)² + 30(-10) - 150 = 1200 - 300 - 150 = 750

ƒ'(x) > 0 so the function is increasing on (-∞, -5).

(b) x = 0

ƒ'(0) = 12(0)² + 30(0) -150 = -150  

ƒ'(x) < 0 so the function is decreasing.

(c) x = 10

ƒ'(0) = 12(10)² + 30(10) -150 = 1200 + 300 - 150 = 1350  

ƒ'(x) > 0 so the function is increasing on (2.5, ∞).

The function is increasing on (-∞, -5) and (2.5, ∞).

80π/3 or about 83.775

step-by-step explanation:

since a cone is 1/3 of a cylinder, we need to find the base's area. since area = πr^2, we get 16π. then, multiplying this by 5, we get 80π. dividing by 3, since the cone's volume is 1/3 of that of a cylinder's, we get 80π/3.

hope this !