Iwill award !

rewrite without absolute value for the given conditions:

1) y=|x−5|+|x+5|, if x > 5

2) y=|x−5|+|x+5|, if x < -5

3) y=|x−5|+|x+5|, -5 < x < 5

1.y=2x

2.y=2x

3.y=10

Step-by-step explanation:

1. Since x is greater than 5, then x-5 is positive and |x+5| is also positive, so we can remove the absolute value and get x-5+x+5 which is 2x.

2. Since x is less than -5, then x-5 will be negative and x+5 will also be negative. So we will still get 2x because the absolute value turns it positive.

3. Since x is between both -5 and 5, x+5 will be positive. So if x is negative it would be 5-x and if x was positive it would be still x+5. It would switch for x-5 so the xs cancel out and ends up as 10.

c

step-by-step explanation:

it isn't d, because the interquartile range is from 27-57. and the interquartile range is basically half the data, it's pretty obvious.

it isn't b, because like i said earlier, the interquartile range is from 27-57. 57-27 is 30. the real range has to be longer

not a either. although it looks like it, 3/4 of the data is not greater than 27. but if c is wrong than this should be correct

the correct answer is c, because 13 is the point in which the plot starts