Line segments jk and jl in the xy-coordinate plane both have a common endpoint j (-4,11) and midpoints an m1 (2,16) and m2 (-3,5) respectively. what is the distance between m1 and m2? round to the nearest tenth

12.1  

Step-by-step explanation:

The dashed line joining M₁ and M₂ is the hypotenuse of a right triangle as shown in red below.

The base of the triangle is

x₂ - x₁ = 2 - (-3) = 2+ 3 = 5

The height of the triangle is

y₂ - y₁ = 16 - 5 = 11

We can now use Pythagoras' theorem to calculate distance between the two midpoints.

x² = 5² + 11² = 25 + 121 = 146

x = √146 = 12.1

The distance between M₁ and M₂ is 12.1.

the polynomial is a perfect square trinomial of the form a^2-2ab+b^2:

option a. true

step-by-step explanation:

9x^2-12x+4

comparing with the form a^2-2ab+b^2

1.) a^2=9x^2

solving for a: square root both sides of the equation:

sqrt(a^2)=sqrt(9x^2)

a=sqrt(9) sqrt(x^2)

a=3x

2.) b^2=4

solving for b: square root both sides of the equation:

sqrt(b^2)=sqrt(4)

b=2

to be a perfet square trinomial 2ab must be equal to 12x. let's check:

2ab = 2 (3x) (2)

2ab = 12x

correct