Prove that the value of the expression: (3^5–3^4)(3^3+3^2) is divisible by 24

need

Step-by-step explanation:

first we expand the whole expression.

(3^5 - 3^4) (3^3 + 3^2)

= 3^8 + 3^7 - 3^7 - 3^6

= 3^8 - 3^6

Note that 3^6 is a common factor.

=3^6 ( 3^2 - 1)

= 3^6 * 8

=3^5 * 3*8

=3^5 * 24

So the result shows that 24 is a factor of the expression.

Therefore, the expression is divisible by 24.

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5/12, or 5: 12

step-by-step explanation: