The combined area of two squares is 45 cenimeters. each side of one square is twice as long as a side of the other square. what is the length of each side of the larger square

The side length of one square would be X, then the side of the second square would be 2X ( twice as long as the first one.)

Area of a square is side x side

The area of the first square would be x times x which becomes x^2.

The area of the second square would be 2x x 2x , which becomes 4x^2.

Now the sum of the two equals 45.

Now you have x^2 + 4x^2 = 45

Simplify to get:

5x^2 = 45

Divide both sides by 5:

x^2 = 45/5

x^2 = 9

Take the square root of each side:

x = √9

x = 3 cm.

The first square has side length x = 3 cm.

The second square was 2x = 2 *3 = 6 cm.

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option

details

step-by-step explanation: