Based on the tree diagram below, what is the probability that a student has lice, given that the student tested positive? round your answer to the nearest tenth of a percent.

a. 77.5%

b. 65.3%

c. 85.9%

d. 57.7%

Answer with explanation:

Probability that  the student is suffering from lice the test shows Positive

Probability that  the student is not suffering from lice and the test shows Positive

Abbreviation used

L = Student has lice

N L=Student has no lice

P T=Test shows Positive

Probability that a student has lice, given that the student tested positive

In terms of Percentages Required Probability

                              = 0.8590 × 100

                               = 85.90 %

Option C

im pretty sure its

(8,15)

step-by-step explanation: