Asubmarine is at a depth of 2 1/3 km below sea level and if it starts ascending at the rate of 800m/h. then find its position after 2 hours?

66 ⅔ m

Step-by-step explanation:

2 ⅓ km can be written in improper form as 5/3 km.

There's 1000 m in 1 km, so we can convert this:

5/3 km × (1000 m / km) = 5000/3 m

The submarine rises at 800 m/h.  So after 2 hours:

distance = rate × time

d = 800 m/h × 2 h

d = 1600 m

So the new position is:

5000/3 m − 1600 m

5000/3 m − 4800/3 m

200/3 m

66 ⅔ m

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step-by-step explanation: