Me with this its super annoying
i have tried but it wants to be super specific so : (

Step-by-step explanation:

Angle CBO = 90 - 2x because the radius meets the tangent at 90°

Angle OCB = Angle CBO= 90 - 2x because base angles of an isosceles triangle are equal (OB and OC are radii - so they are equal)

Angle DCO = Angle CDO = x because base angles of an isosceles triangle are equal. (OC and OD are radii - so they are equal)

Angle BCD = Angle DCO + Angle OCB

So Angle BCD = x + (90 - 2x)

Angle BCD = 90 - x

therefore, Angle DOB = 2 × (90 - x)

Angle DOB = 180 - 2x because the angle at the centre is twice the angle at the circumference.

Angle ODA and Angle OBA are both 90° as the angle between the radius and the tangent is 90°

hence, you can work out Angle DAB because angles in a quadrilateral add up to 180°.

Angle DAB = y

y = 360 - 90 - 90 - (180 - 2x)

expand brackets

y = 360 - 90 - 90 - 180 + 2x

y = 2x (angles in a quadrilateral add up to 360°)

the median here is 25. your lowest value is 14 and highest value is 48. to find the third quartile, find the medium number in between 25 and 48 which would be 42 i believe.