Swhich point is a solution to the linear inequality y< -1/2x+2 (2,3) (2,1) (3,-2) (-1,3)

Step-by-step explanation:

Put the coordinates of the points to the inequality and check:

y < -1/2x + 2

for (2, 3) → x = 2, y = 3

3 < -1/2(2) + 2

3 < -1 + 2

3 < 1     FALSE

for (2, 1) → x = 2, y = 1

1 < -1/2(2) + 2

1 < -1 + 2

1 < 1    FALSE

for (3, -2) → x = 3, y = -2

-2 < -1/2(3) + 2

-2 < -1.5 + 2

-2 < 0.5      TRUE

for (-1, 3) → x = -1, y = 3

3 < -1/2(-1) + 2

3 < 1/2 + 2

3 < 2 1/2      FALSE

ian gonna lie that is way to much