You are getting ready to watch a fireworks display and are sitting about 300 feet away from the launch pad. the angle for you to see the fireworks is about 35°. if the fireworks are launched vertically into the sky, what is the height of the fireworks when they explode?

210.06 feet

Step-by-step explanation:

This is a classic right triangle trig problem.  The distance from the launch pad is the measure of the base of the right triangle.  The angle of elevation, 35, is the base angle (not the right angle).  How high the fireworks go up is the height of the triangle.  You have the reference angle of 35, the side adjacent to it, 300, and you're looking for the side length across from it, y.  The trig ratio that relates a reference angle to the sides opposite it and adjacent to it is the tangent ratio.  Setting that up:

Solving for y:

y = 300 tan(35)

On your calculator in degree mode find y to be 210.06 feet.

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