Acamera manufacturer spends $1,800 each day for overhead expenses plus $9 per camera for labor and materials. the cameras sell for $18 each. a. how many cameras must the company sell in one day to equal its daily costs? b. if the manufacturer can increase production by 50 cameras per day, what would their daily profit be?

Amount of money spent per day = $1800

Cost of overhead expenses per day for labor and materials = $9

Selling price of each camera = $18

a. Let us assume the number of cameras manufactured per day = x dollars

Then

Cost of cameras sold in 1 day = 18x

So

18x = 1800 + 9x

18x - 9x = 1800

9x = 1800

x = 200

From the above deduction, we can conclude that the number cameras sold per day is 200

b. Daily selling amount of 250 cameras = 250 * 18

                                                              = 4500 dollars

Daily manufacturing price of 250 cameras = 1800 + (9 * 250)

                                                                   = 4050 dollars

Then

Daily profit = 4500 - 4050

                 = 450 dollars

solution:

as, mean is defined as sum of all the observations divided by total number of observations.

and , median is mid value of the data whether arranged in ascending order or descending order.

consider, roadsters:

2,3,4,5,6,7,8,9

mean =

also, median= , because number of observations is even, so median is mean of two mid values.

now, coming to bandits

2,3,4,5,6

mean =  

median = 4, as number of observations is odd.

so, roadsters has greater median as well mean than bandits.

→option a is true about the repairs performed on 2 types of cars:

bandits have lower median and mean than roadsters.

i need a picture

step-by-step explanation: