For the month of june in a certain city, 41% of the days are cloudy. also in the month of june in the same city, 21% of the days are cloudy and rainy. what is the probability that a randomly selected day in june will be rainy if it is cloudy?

0.5122 or 51.22%

Step-by-step explanation:

In a certain city, in June Probability of cloudy days = P(cloudy) = 0.41

Probability of cloudy and rainy = P(cloudy and rainy) = 0.21

Probability of rainy if we already know it is cloudy =

= = 0.512195122 ≈ 0.5122

Therefore, the probability that a randomly selected day in June will be rainy if it is cloudy is 0.5122 or 51.22%

yes

step-by-step explanation:

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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