The distance traveled, in feet, of a ball dropped from a tall building is modeled by the equation d(t) = 16t2 where d equals the distance traveled at time t seconds and t equals the time in seconds. what does the average rate of change of d(t) from t = 2 to t = 5 represent? \

The rate of change determines the average speed of the ball when it is dropped from the building.

Step-by-step explanation:

d(t) = 16t^2

when t = 2

d(t) = 16 (2)²

d(t) = 64

when t = 5

d(t) = 16 (5)²

d(t) = 400

Average speed/rate of change = distance/time = 64/2 = 32 feet

Average speed/rate of change = distance/time = 400/5 = 80 feet

The rate of change determines the average speed of the ball when it is dropped from the building.

!!

< 4, -5>

step-by-step explanation:

starting from g. we move 4 right and then 5 down to get to h. that means the vector is < 4, -5>

30 feet

step-by-step explanation:

that would be 2 1/2 * 12

= 24 + 6

= 30 feet   (answer)