Find an equation for the line perpendicular to y=−1/7x+2 with x-intercept at x = -7.
write your answer in the form y=mx+b.
y=

Step-by-step explanation:

To find the slope of a line which is perpendicular to another line, you need to find the opposite reciprocal of the first line's slope.

To find the opposite, flip the slope's sign. Your original slope is , so your opposite slope is positive .

To find the reciprocal, flip the fraction. This changes your slope from to , which may be written as just 7.

Therefore, your slope is 7.

To find your b term (your y-intercept) given that your x-intercept is -7, you can make use of point-slope form.

(m=slope)

If your x-intercept is -7, then the point at which your line intersects the x-axis is (-7, 0).

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}