Then find the area s of the region.

y=2 x^2, y^2=1/2 x

Recall that the area under a curve and above the x axis can be computed by the definite integral.  If we have two curves

        y = f(x) and y = g(x)

such that 

        f(x) > g(x) 

then the area between them bounded by the horizontal lines x = a and x = b is

To remember this formula we write

y=3x+4

step-by-step explanation:

given the points a(0,4) and b(-4, -8)

eqn of line ab: (y-4)/(x-0)=(-8-4)/(-4-0)

(y-4)/x=-12/-4=3

y=3x+4