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Mathematics, 17.07.2019 16:10 lazavionadams81

(a) w = x^2 + y^2 + 2ixy ;
(b) w = x(x^2 - 3y^2) - iy(3x^2 - y^2) ;
(c) w =
(2(x^2 + y^2) - (x + iy))/
(4(x^2 + y^2) - 4x + 1)

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Answers: 3

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(a) w = x^2 + y^2 + 2ixy ;
(b) w = x(x^2 - 3y^2) - iy(3x^2 - y^2) ;
(c) w =
(2(x...
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