In a study of the accuracy of fast food drive-through orders, restaurant a had 277 accurate orders and 67 that were not accurate. a. construct a 90% confidence interval estimate of the percentage of orders that are not accurate. b. compare the results from part (a) to this 90% confidence interval for the percentage of orders that are not accurate at restaurant b: 0.174less thanpless than0.244. what do you conclude?

Step-by-step explanation:

Given that in a study of the accuracy of fast food drive-through orders, Restaurant A had 277 accurate orders and 67 that were not accurate.

Sample proportion for non accurate =

Std error =

Margin of error = 1.645 * std error

Confidence Interval:

±4.23

Range for the true population proportion:

19.96% to 28.42%

b) 17.40 to 24.40 is given. Mid value is 20.9% which must have been the sample proportion.

24.19% observed proportion lies in both the intervals.

there is no

the answer is d. (1.2, -4.7) on edgn

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