Calculate the amount of heat (in kilojoules) required to vaporize 2.60 kg of water at its boiling point. (? hvap=40.7 kj/mol at 100? c.) express your answer to three significant figures and include the appropriate units.

heat require for vaporize = 5873.98 kJ

Step-by-step explanation:

Given data

mass of water = 2.60 kg

Hvap = 40.7 kJ/mol

to find out

Calculate the amount of heat

solution

we know heat required for 1 mol of water to vaporize at 100 degree c is 40.7 kg

and

we know water weight of 1 mol is  18.015 gram

so mole of 2.60 kg water is  = 2600 / 18.1015

that is = 144.3241 mol

so heat require for vaporize 144.3241 mol of water is = 144.3241 × 40.7

heat require for vaporize = 5873.98 kJ

answer: b.

step-by-step explanation:

the y coordinate for point b is 0, and answer b is the only one with that y coordinate.

part a

in a city ice cream is mostly only bought when the temperature is very high as ice cream cools down our

so we can derive the conclusion that as the temperature increases the number of ice creams sold also increases

part b

y intercept is 5

slope is 2

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