The lengths of pregnancies in a small rural village are normally distributed with a mean of 261 days and a standard deviation of 17 days. in what range would you expect to find the middle 95% of most pregnancies?

range is between 294.32 and 227.68 expect the middle 95% of most pregnancies

Step-by-step explanation:

Given data

mean  μ  = 261 days

standard deviation SD = 17 days

most pregnancies = 95%

to find out

In what range expect to find the middle 95% of most pregnancies

solution

we have Z value for 95% is 1.96

so Confidence interval  = mean +/- 1.96×SD

put vale

Confidence interval = 261 +/- 1.96(17)

Confidence interval = 294.32 and 227.68

range is between 294.32 and 227.68 expect the middle 95% of most pregnancies

hi,

6x times 4 is 24x and 5 times 4 is 20, so the answer is 24x+20.

hope this and for a little humor i am groot.