If the length of one leg of a right triangle is 4 and the hypotenuse is √65 , what is the length of the other leg?

7

Step-by-step explanation:

Using Pythagoras' identity on the right triangle

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides.

let x be the other leg, then

x² + 4² = ( )²

x² + 16 = 65 ( subtract 16 from both sides )

x² = 49 ( take the square root of both sides )

x = = 7

That is the other leg is 7 units

To answer this question you must use Pythagorean theorem

a and b are the legs (the sides that form a perpendicular/right angle)

c is the hypotenuse (the side opposite the right angle)

In this case...

a = 4

b = unknown

c =

^^^Plug these numbers into the theorem

Simplify

16 + b² = 65

solve for b

+ 16 = 65

= 49

To completely isolate b you will have to get rid of the square attached to it. To do this you will need to take the square root of both sides

√b² = √49

b = 7

Hope this helped!

~Just a girl in love with Shawn Mendes

the equation for this situation is y=122+45. to solve the equation you would add 45 and 122 to get a total of 167lbs. in conclusion, grace's weight eight weeks ago was 167lbs.