Find a12 of the sequence 1/4, 7/12, 11/12, 5/4

1/4 = 3/12, and 5/4 = 15/12, so it looks like there's a common difference between terms of 4/12 = 1/3. The the -th term in the sequence is given recursively by

By substitution, we get

and doing this again and again until we stop with an expression containing , we find that

Then the 12th term in the sequence is