If a, b, and c are mutually exclusive events with p(a) = 0.2, p(b) = 0.3, and p(c) = 0.4, determine the following probabilities: a. p(a ∪ b ∪ c) b. p(a ∩ b ∩ c) c. p(a ∩ b) d. p[(a ∪ b) ∩ c] e. p(a′ ∩ b′ ∩ c′)

a. The events are mutually exclusive, so

b. For the same reason,

Another way to see this is to use the result from part (a), and the inclusion/exclusion principle:

and the right side reduces to 0.

c. Same as (b),

d. Same as (b),

We can also use the distributivity rule for unions and intersections to write

e. If the is the complement of , then by DeMorgan's law,

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step-by-step explanation:

well if he bought them at 5 cedis each sold them at 7 cedis each then he would make a profit of 2 cedis of each book. if in total he made 150 cedis profit that means he sold 75 books. he lost 12 books at the start so that means he originally bought a total of 82 books.

step-by-step explanation: