The weights, in pounds, of the cats in an animal adoption center are normally distributed. if a random sample of cats is taken and the confidence interval is (7.9,12.7), what is the margin of error

2.4

Step-by-step explanation:

Given : The weights, in pounds, of the cats in an animal adoption center are normally distributed.

The confidence interval is (7.9,12.7)           (1)

Let be the sample mean of the weights, in pounds, of the cats in an animal adoption center.

We know that the confidence interval for population mean is given by :-

     (2)

From (1) and (2)

Subtracting (3) from (4), we get

Hence, the margin of error is E = 2.4

it should be a and d. lmk if i'm wrong xd

34.5 cm

step-by-step explanation:

generally for a circular segment of angle, θ° and radius r

arc length

= (θ/360) x circumference

= (θ/360) x 2πr

in our case, θ = 60°, π=3.142 and r = 33 cm

substitute into above formula

arc length

= (60/360) x 2(3.142)( 33) = 34.5 cm