Can someone explain to me how to do questions 6-8 because i understand how to do 3-5 now. can you explain to me how you do this ? i have a test tomorrow

see explanation

Step-by-step explanation:

Using the midpoint formula to equate the x and y coordinates of the endpoints to the x and y coordinates of the midpoint, that is

(6)

let ( x, y ) be the coordinates of the required endpoint, then

x → = 2 ( multiply both sides by 2 )

  x + 6 = 4 ( subtract 6 from both sides )

x = - 2 and

y → = 0 , thus

y + 2 = 0 ( subtract 2 from both sides )

y = - 2

Coordinates of the other endpoint = (- 2, - 2)

(7)

x → = - 1 ( multiply both sides by 2 )

x - 4 = - 2 ( add 4 to both sides )

x = 2 and

y→ = - 1 ( multiply both sides by 2 )

y + 3 = - 2 ( subtract 3 from both sides )

y = - 5

Coordinates of the other endpoint = (2, - 5)

(8)

x → = 2 ( multiply both sides by 2 )

x + 7 = 4 ( subtract 7 from both sides )

x = - 3 and

y → = 1 ( multiply both sides by 2 )

y + 3 = 2 ( subtract 3 from both sides )

y = - 1

Coordinates of the other endpoint = (- 3, - 1)

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

part d

step-by-step explanation:

theresa talked her parents into getting sd cards for her phone and her brother’s phone. inserting an sd card into a phone gives it more storage. they both get 8-gigabyte sd cards. how many bits of storage come with each sd card? type your answer in both scientific and standard notation.