Find three consecutive integers whose sum is 441

146, 147 and 148

Step-by-step explanation:

Let the three integers be x, x+1, and x+2.

(they are consecutive)

Now, we are given that their sum is 441.

So,

(x) + (x+1) + (x+2) = 441

3x + 3 = 441

3x = 438

x = 438/3

x = 146

Thus, the integers are:

x = 146

x+1 = 147

x+2 = 148

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answer: h

step-by-step explanation:

x=half

step-by-step explanation: