The number of vibrations n n per second of a nylon guitar string varies directly with the square root of the tension t t and inversely with the length l l of the string. if the tension is 256 256 kilograms when the number of vibrations per second is 15 15 and the length is 0.6 0.6 meters, find the tension when the length is 0.3 0.3 meters and the number of vibrations is 12 12 .

Step-by-step explanation:

We know that:

: The number of vibrations per second of the nylon guitar string.

: Tension.

: The length of the string.

Since    varies directly with the square root of the   and inversely with  , the equation has the following form:

Where "k" is the constant of variation.

Knowing that when and , , we can find the value of "k":

Finally, in order to find the tension when the length is 0.3 meters and the number of vibrations is 12, you need to substitute these values and the value of "k" into and solve for :

only 10/60 isn't equivalent

hope this : )

option: d is the correct answer.

d) none of the above.

step-by-step explanation:

clearly from the figure attached to the question we could see that there is no shape given. hence without any shape given in the figure and after rotation we can't obtained a square pyramid.

since, to obtain a image we need a proper figure of the pre-image so that it can be transformed.

hence, the correct answer is:

d) none of the above.

step-by-step explanation: