Find the general solution of the differential equation: y' + 3x^2 y = 0

The general solution of the differential equation y' + 3x^2 y = 0 is:

Step-by-step explanation:

This equation its a Separable First Order Differential Equation, this means that you can express the equation in the following way:

, notice that the notation for y' is changed to

Then you can separate the equation and put the x part of the equation on one side and the y part on the other, like this:

The Next step is to integrate both sides of the equation separately and then simplify the equation.

For the differential equation in question y' + 3x^2 y = 0 the process is:

Step 1: Separate the x part and the y part

Step 2: Integrate both sides

Step 3: Solve the integrals

Simplify the equation:

To solve the Logarithmic expression you have to use the exponential e

Then the solution is:

answer: y = -12x + 108

step-by-step explanation: do (y = m x+b) formula.

option c) graph of line going through 1, 4 and 3, 10

step-by-step explanation:

let y equal to margo's coin collection

let x equal to number of years

at the begining x=0, y=1 → point=(x,y)→point=(0,1)

she adds 3 coins per year, then y=1+3x

at x=1, y=1+3(1)=1+3→y=4→point=(x,y)→point=(1,4)

at x=3, y=1+3(3)=1+9→y=10→point=(x,y)→point=(3,10)

the graph of line going through (1, 4) and (3, 10), then the option c is the correct.