Aspy is trying to escape. she must get by four guards. each guard takes half of her remaining money. she then $64 for her plane ticket. how much money does she have to start with in order to make her escape?

The spy must have at the start the amount of $1,024 in order to escape

Step-by-step explanation:

Let

a ------> amount of money that the spy must have at the start to escape

y ----> the remaining money

x ----> the number of guards

In this problem the remaining money is going to be reduced by half, every time the spy passes through a guard, so we can use an exponential function of the form

where

a is the initial value (amount of money at the start)

b is the base

b=(1-r)

r is the rate of decay

In this problem we have

r=50% -----> r=0.50

The value of b is

b=(1-0.50)=0.50

substitute

we know that

In order to escape after the fourth guard the amount of money remaining must be equal to $64

so

For x=4, y=$64

substitute in the equation and solve for a

therefore

The spy must have at the start the amount of $1,024 in order to escape

  5.   y=6; de=7; fg=8

  6.   x=4.2; jl=14.2; mn=13

step-by-step explanation:

when chords cross inside a circle, the product of the segment lengths is a constant.

5. dh×eh = fh×gh

  y = gh = dh×eh/fh = 3×4/2 . . . divide by the coefficient of gh

  y = 6

of course, the total chord length is the sum of the lengths of its segments.

  de = dh +eh = 3+4 = 7

  fg = fh +gh = 2+6 = 8

6. this problem works the same way as the previous one.

  x = lk = mk×nk/jk = 6×7/10 = 4.2

  jl = jk +lk = 10 +4.2 = 14.2

  mn = mk +nk = 6 +7 = 13

comment on chords and secants

you can think of the points h (problem 5) and k (problem 6) as points where the chords meet. a chord is part of a secant line, a line that intersects the circle in two points. one can also consider these points (h or k) to be the points where the respective secant lines meet.

then, the product that is a constant is the product of the distance from the meeting point (h or k) to one circle intersection with the distance from that meeting point to the other circle intersection. for problem 5, the constant is the product hd×he = hf×hg.

it turns out that this rule regarding the products of lengths to points of intersection is also true when the secants intersect outside the circle.

that is, you only need to remember one rule to work both kinds of problems.

false

step-by-step explanation:

the meaning of changing is to edit or make something different.

but transmitting means cause (something) to pass on from one place or person to another.

there 2 different things