Suppose we have an unfair coin that its head is twice as likely to occur as its tail. a)if the coin is flipped 3 times, what is the probability of getting exactly 1 head? give your answer to four decimal places b)if the coin is flipped 5 times, what is the probability of getting exactly 2 tails? give your answer to four decimal places c)if the coin is flipped 4 times, what is the probability of getting at least 3 tails? give your answer to four decimal places

a) 0.2222, b) 0.3292, c) 0.1111

Step-by-step explanation:

Since we have given that

Let the probability of getting head be p.

Since,  its head is twice as likely to occur as its tail.

a)If the coin is flipped 3 times, what is the probability of getting exactly 1 head?

So, here, n  = 3

Now,

b)If the coin is flipped 5 times, what is the probability of getting exactly 2 tails?

2 tails means 3 heads.

So, it becomes,

c)If the coin is flipped 4 times, what is the probability of getting at least 3 tails?

Hence, a) 0.2222, b) 0.3292, c) 0.1111

answer: $34.31

step-by-step explanation:

$11.99 x 3 = $35.97

$35.97 - 10% = $32.37

$32.37 + 6% = $34.31

+25 = x

step-by-step explanation:

here x is the hypotenuse of a right triangle whose legs are 7 and 24.   by the pythagorean theorem, 7² + 24² must equal x²:

x² = 49 + 576 = 625.   thus, x = +√625 = +25 = x