Supposed that over a period of several years the average number of deaths from a certain noncontagious disease has been 5. if the number of deaths from this disease follows the poisson distribution, what is the probability that during the current year: (e −1 = 0.37, e−2 = 0.14, e−3 = 0.05, e−4 = 0.02, e−5 = 0.01) (a) there will be no deaths from the disease? (b) two or more people will die from the disease?

a) 0.00673

b)0.9596

Step-by-step explanation:

Let be X the random variable : ''Number of deaths from this disease''

X ~ P(λt)

Where λ is number of events per unit time and λt is number of events over time period t

In our exercise t = 1 year

λ : lambda

The probability function for X is :

x ≥ 0

a)

b)

c: y > - 1/6x + 1

step-by-step explanation:

dashed line - meaning this < or > also not equal

solid line - meaning this < or > also equal

your answer is c because y > means up & it's shaded up, but y < means down

hope this ! : )

2

step-by-step explanation: