Mathematics, 09.10.2019 04:10 deasiamonay14
Rahul solved the equation 2(x – ) – 2 left-parenthesis x minus startfraction 1 over 8 endfraction right-parenthesis minus startfraction 3 over 5 endfraction x equals startfraction 55 over 4 endfraction x = 2 left-parenthesis x minus startfraction 1 over 8 endfraction right-parenthesis minus startfraction 3 over 5 endfraction x equals startfraction 55 over 4 endfraction . in which step did he use the addition property of equality?
Answers: 3
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Rahul solved the equation 2(x – ) – 2 left-parenthesis x minus startfraction 1 over 8 endfraction ri...
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