Find the value of x if b is the midpoint of ac, ab=3-2x, bc=x-12

ANSWER:

The value of x if b is the midpoint of AC, AB=3 - 2x, BC = x - 12 is 5

SOLUTION:    

Given, B is the midpoint of points A and C

And given the distance values of AB and BC

i.e. AB = 3 – 2x and BC = x -12

we need to find the value of x  

now, as B is the midpoint of A and C  

Distance between A and B equals to Distance between B and C . So we get,

AB = BC

3 – 2x = x – 12

3 – 2x – (x – 12) = 0

3 – 2x –x +12 = 0

3 -3x + 12 = 0

-3x +15 = 0

-3x = -15

3x = 15

x =

x = 5

Hence the value of x is 5.

answer: i forgot

step-by-step explanation: