This extreme value problem has a solution with both a maximum value and a minimum value. use lagrange multipliers to find the extreme values of the function subject to the given constraint. f(x, y, z) = 10x + 10y + 3z; 5x2 + 5y2 + 3z2 = 43

Answer with Step-by-step explanation:

We are given that

We have to find the extreme values of the function.

Therefore,

Substitute the values in g(x)

Then, we get

When then,

When

Then,

Hence, maximum value of f(x,y,z) is 23 at (2,2,1) and minimum value of f(x,y,z) is -23 at (-2,-2 ,-1).

75

step-by-step explanation:

you do x-29=46 (the number of cantaloupes sold)

in order to find x, you have to find what minus 29 equals 46, meaning you'd have to add 29 to 46.

29+46=75

if you replace x with 75, the equation looks like:

75-29=46

x=75

i think it is c hope that