Quadrilateral fghj is dilated according to the rule do, two-thirds(x, y)(two-thirds x, two-thirds y) to create the image quadrilateral f'g'h'j', which is not shown. on a coordinate plane, quadrilateral f g h j has points (negative 5, negative 4), (negative 3, negative 2), (negative 1, negative 4), (negative 3, negative 6). what are the coordinates of point j'?

the answer is c: divide the arc's degree measure by 360°, then multiply by the circumference of the circle.

see below

step-by-step explanation:

x+2> 6

subtract 2 from each side

x+2-2 > 6-2

x > 4

there is an open circle at 4 since is it is greater than and the line goes to the right

ome people is not even worth it to even try it in the air.

step-by-step explanation:

the correct answers are 1, 2, 4, and 5! i just got it right!